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x^2+93x-40=0
a = 1; b = 93; c = -40;
Δ = b2-4ac
Δ = 932-4·1·(-40)
Δ = 8809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(93)-\sqrt{8809}}{2*1}=\frac{-93-\sqrt{8809}}{2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(93)+\sqrt{8809}}{2*1}=\frac{-93+\sqrt{8809}}{2} $
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